Keerthana
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(i) 3x² + 11x + 10 = 0

(ii) 2y² + 11y + 14 = 0

a

x ≥ y

b

x ≤ y

c

x > y

d

x < y

e

x = y or no relation can be established between x & y.

Answer : Option A
Explanation :

I. 3x2+11x+10=03{x^2} + 11x + 10 = 0

3x2+6x+5x+10=03{x^2} + 6x + 5x + 10 = 0

3x(x+2)+5(x+2)=03xleft( {x + 2} ight) + 5left( {x + 2} ight) = 0

x=2,53x = - 2,frac{{ - 5}}{3}II. 2y2+11y+14=02{y^2} + 11y + 14 = 0

2y2+7y+4y+14=02{y^2} + 7y + 4y + 14 = 0

y(2y+7)+2(2y+7)=0yleft( {2y + 7} ight) + 2left( {2y + 7} ight) = 0

$egin{array}{*{20}{c}}

{y = - 2, - frac{7}{2}}\

{X ge y}

end{array}$

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