Directions(Q.21 to Q.24 ):   In each of these questions, two equations (i) and (ii) are given, you h
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Directions(Q.21 to Q.24 ):

In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.


II. 15y2+16y+4=015{y^2} + 16y + 4 = 0

a

x > y

b

x < y

c

x ≥ y

d

x ≤ y

e

x = y or no relation can be established between x & y.

Answer : Option B
Explanation :

I. 2x2+9x+9=02{x^2} + 9x + 9 = 0

2x2+(6+3)x+9=02{x^2} + left( {6 + 3} ight)x + 9 = 0

2x(x+3)+3(x+3)=02xleft( {x + 3} ight) + 3left( {x + 3} ight) = 0

x=32,3x = frac{{ - 3}}{2}, - 3

II. 15y2+16y+4=015{y^2} + 16y + 4 = 0

15y2+10y+6y+4=015{y^2} + 10y + 6y + 4 = 0

5y(3y+2)+2(3y+2)=05yleft( {3y + 2} ight) + 2left( {3y + 2} ight) = 0

y=25,23y = frac{{ - 2}}{5},frac{{ - 2}}{3}

x<yx < y

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Directions(Q.21 to Q.24 ): In each of these questions, two equations (i) and (ii) are given, you h