**Directions(Q.21 to Q.24 ): **

** **

In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.

**II. **$15{y^2} + 16y + 4 = 0$

Answer : Option B

Explanation : I. $2{x^2} + 9x + 9 = 0$

$2{x^2} + left( {6 + 3} ight)x + 9 = 0$

$2xleft( {x + 3} ight) + 3left( {x + 3} ight) = 0$

$x = frac{{ - 3}}{2}, - 3$

**II. **$15{y^2} + 16y + 4 = 0$

$15{y^2} + 10y + 6y + 4 = 0$

$5yleft( {3y + 2} ight) + 2left( {3y + 2} ight) = 0$

$y = frac{{ - 2}}{5},frac{{ - 2}}{3}$

$x < y$** **

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