Directions(Q.26 to Q.30 ):

In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer

II. $2{y^2} - y - 15 = 0$

I. ${x^2} - 13x + 40 = 0$

${x^2} - 5x - 8x + 40 = 0$

$xleft( {x - 5} ight) - 8left( {x - 5} ight) = 0$

$x = 5,8$II. $2{y^2} - y - 15 = 0$

$2{y^2} - 6y + 5y - 15 = 0$

$2yleft( {y - 3} ight) + 5left( {y - 3} ight) = 0$

$y = 3, - 5/2$

$x > y$