KeerthanaPosted on Equation of line 3x+y−8=0sqrt{3} x+y-8=03x+y−8=0 can be represented in normal form as a3x−y−8=0sqrt{3} x-y-8=03x−y−8=0 b3x2−y2−82=0frac{sqrt{3} x}{2}-frac{y}{2}-frac{8}{2}=023x−2y−28=0 c3x2+y2−82=0frac{sqrt{3} x}{2}+frac{y}{2}-frac{8}{2}=023x+2y−28=0 d3x+y−4=0sqrt{3} x+y-4=03x+y−4=0 Answer : Option CExplanation : Equation of line in normal form can be written as axa2+b2+bya2+b2+ca2+b2=0frac{a x}{sqrt{a^{2}+b^{2}}}+frac{b y}{sqrt{a^{2}+b^{2}}}+frac{c}{sqrt{a^{2}+b^{2}}}=0a2+b2ax+a2+b2by+a2+b2c=0 ⇒3x32+12+y32+11−832+12=0Rightarrow frac{sqrt{3} x}{sqrt{3}^{2}+1^{2}}+frac{y}{sqrt{sqrt{3}^{2}+1^{1}}}-frac{8}{sqrt{sqrt{3}^{2}+1^{2}}}=0⇒32+123x+32+11y−32+128=0 3x4+y4−84=0frac{sqrt{3} x}{sqrt{4}}+frac{y}{sqrt{4}}-frac{8}{sqrt{4}}=043x+4y−48=0 ⇒3x2+y2−82=0Rightarrow frac{sqrt{3} x}{2}+frac{y}{2}-frac{8}{2}=0⇒23x+2y−28=0 Rate This:NaN / 5 - 1 votesAdd comment