The respective ratio between the height of tower and the point at some distance from its foot is 57 $: 19 sqrt{3}$. What is the angle (in degrees) of elevation of the top of the tower?

AB = Tower

BC = Distance from the foot

$an heta=frac{mathrm{AB}}{mathrm{BC}}=frac{57}{19 sqrt{3}}=sqrt{3}$

$Rightarrow an heta= an 60^{circ} Rightarrow heta=60^{circ}$