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(1.1)3+(0.7)3(1.1)21.1×0.7+(0.7)2कामूल्यक्याहै?\frac{(1.1)^{3}+(0.7)^{3}}{(1.1)^{2}-1.1 \times 0.7+(0.7)^{2}} का मूल्य क्या है?

a

0.4

b

0.7

c

1.1

d

1.8

Answer : Option D
Explanation :

Let 1.1 = a and 0.7 = b

\therefore अभिव्यक्ति =a3+b3a2ab+b2=(a+b)(a2ab+b2)a2ab+b2=\frac{a^{3}+b^{3}}{a^{2}-a b+b^{2}}=\frac{(a+b)\left(a^{2}-a b+b^{2}\right)}{a^{2}-a b+b^{2}}

=a+b=1.1+0.7=1.8\quad=a+b=1.1+0.7=1.8

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