KeerthanaPosted on (3 + 1) (32 + 1) (34 + 1) (38 + 1) का सरलीकृत मूल्य क्या है? (316 + 1) ? a(3128−1)2frac{left(3^{128}-1 ight)}{2}2(3128−1) b(364−1)2frac{left(3^{64}-1 ight)}{2}2(364−1) c(332−1)2frac{left(3^{32}-1 ight)}{2}2(332−1) d(316−1)2frac{left(3^{16}-1 ight)}{2}2(316−1) Answer : Option CExplanation : Expression = (3 + 1) (32 + 1) (34 + 1) (38 + 1) (316 + 1) (3−1)(3+1)(32+1)=(34+1)(38+1)(316+1)(3−1)egin{aligned} &(3-1)(3+1)left(3^{2}+1 ight) \=& frac{left(3^{4}+1 ight)left(3^{8}+1 ight)left(3^{16}+1 ight)}{(3-1)} end{aligned}=(3−1)(3+1)(32+1)(3−1)(34+1)(38+1)(316+1) =(32−1)(32+1)(34+1)(38+1)(316+1)2=frac{left(3^{2}-1 ight)left(3^{2}+1 ight)left(3^{4}+1 ight)left(3^{8}+1 ight)left(3^{16}+1 ight)}{2}=2(32−1)(32+1)(34+1)(38+1)(316+1) [∵(a+b)(a−b)=a2−b2]left[ecause(a+b)(a-b)=a^{2}-b^{2} ight][∵(a+b)(a−b)=a2−b2] =(34−1)(34+1)(38+1)(316+1)2=frac{left(3^{4}-1 ight)left(3^{4}+1 ight)left(3^{8}+1 ight)left(3^{16}+1 ight)}{2}=2(34−1)(34+1)(38+1)(316+1) =(38−1)(38+1)(316+1)2=frac{left(3^{8}-1 ight)left(3^{8}+1 ight)left(3^{16}+1 ight)}{2}=2(38−1)(38+1)(316+1) =(316−1)(316+1)2=332−12=frac{left(3^{16}-1 ight)left(3^{16}+1 ight)}{2}=frac{3^{32}-1}{2}=2(316−1)(316+1)=2332−1 Rate This:NaN / 5 - 1 votesAdd comment