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(3 + 1) (32 + 1) (34 + 1) (38 + 1) का सरलीकृत मूल्य क्या है? (316 + 1) ?

a

(31281)2frac{left(3^{128}-1 ight)}{2}

b

(3641)2frac{left(3^{64}-1 ight)}{2}

c

(3321)2frac{left(3^{32}-1 ight)}{2}

d

(3161)2frac{left(3^{16}-1 ight)}{2}

Answer : Option C
Explanation :

Expression = (3 + 1) (32 + 1) (34 + 1) (38 + 1) (316 + 1)

(31)(3+1)(32+1)=(34+1)(38+1)(316+1)(31)egin{aligned} &(3-1)(3+1)left(3^{2}+1 ight) \=& frac{left(3^{4}+1 ight)left(3^{8}+1 ight)left(3^{16}+1 ight)}{(3-1)} end{aligned}

=(321)(32+1)(34+1)(38+1)(316+1)2=frac{left(3^{2}-1 ight)left(3^{2}+1 ight)left(3^{4}+1 ight)left(3^{8}+1 ight)left(3^{16}+1 ight)}{2}

[(a+b)(ab)=a2b2]left[ecause(a+b)(a-b)=a^{2}-b^{2} ight]

=(341)(34+1)(38+1)(316+1)2=frac{left(3^{4}-1 ight)left(3^{4}+1 ight)left(3^{8}+1 ight)left(3^{16}+1 ight)}{2}

=(381)(38+1)(316+1)2=frac{left(3^{8}-1 ight)left(3^{8}+1 ight)left(3^{16}+1 ight)}{2}

=(3161)(316+1)2=33212=frac{left(3^{16}-1 ight)left(3^{16}+1 ight)}{2}=frac{3^{32}-1}{2}

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