KeerthanaPosted on (cosec2A−1)cosecAfrac{sqrt{left(operatorname{cosec}^{2} A-1 ight)}}{operatorname{cosec} A}cosecA(cosec2A−1) बराबर है acosecA bcosA csinA dsecA Answer : Option BExplanation : cosec2A−1cosecA=cot2AcosecA=cotAcosecAfrac{sqrt{operatorname{cosec}^{2} A-1}}{operatorname{cosec} A}=frac{sqrt{cot ^{2} A}}{operatorname{cosec} A}=frac{cot A}{operatorname{cosec} A}cosecAcosec2A−1=cosecAcot2A=cosecAcotA =cosAsinA×sinA=cosA=frac{cos A}{sin A} imes sin A=cos A=sinAcosA×sinA=cosA [∴cosecA.sinA=1][ herefore operatorname{cosec} A . sin A=1][∴cosecA.sinA=1] Rate This:NaN / 5 - 1 votesAdd comment