(i) 2x^³ = √256

(ii) 2y^² – 9y + 10 = 0

$2{x^3} = 16$

${x^3} = 8$

$x = 2$

$2{y^2} - 9y + 10 = 0$

$2{y^2} - left( {5 + 4} ight)y + 10 = 0$

$2{y^2} - 5y - 4y + 10 = 0$

$yleft( {2y - 5} ight) - 2left( {2y - 5} ight) = 0$

$y = 2,frac{5}{2}$

$x le y$