(i) 6x^² – 11x + 4 = 0

(ii) 3y^² – 5y + 2 = 0

I. $6{x^2} - 11x + 4 = 0$

$6{x^2} - left( {8 + 3} ight)x + 4 = 0$

$6{x^2} - 8x - 3x + 4 = 0$

$2xleft( {3x - 4} ight) - 1left( {3x - 4} ight) = 0$

$x = frac{1}{2},frac{4}{3}$II. $3{y^2} - 5y + 2 = 0$

$3{y^2} - left( {3 + 2} ight)y + 2 = 0$

$3{y^2} - 3y - 2y + 2 = 0$

$3yleft( {y - 1} ight) - 2left( {y - 1} ight) = 0$

$y = 2/3,1$

No relation between x and y