KeerthanaPosted on (sin35∘cos55∘)2−(cos55∘sin35∘)2+2sin30∘left(frac{sin 35^{circ}}{cos 55^{circ}} ight)^{2}-left(frac{cos 55^{circ}}{sin 35^{circ}} ight)^{2}+2 sin 30^{circ}(cos55∘sin35∘)2−(sin35∘cos55∘)2+2sin30∘ is equal to a1 b2 c–1 d0 Answer : Option AExplanation : (sin35∘cos55∘)2−(cos55∘sin35∘)2+2sin30∘left(frac{sin 35^{circ}}{cos 55^{circ}} ight)^{2}-left(frac{cos 55^{circ}}{sin 35^{circ}} ight)^{2}+2 sin 30^{circ}(cos55∘sin35∘)2−(sin35∘cos55∘)2+2sin30∘ =(sin(90∘−55∘)cos55∘)2−(cos55∘sin(90∘−55∘))2+2×12=left(frac{sin left(90^{circ}-55^{circ} ight)}{cos 55^{circ}} ight)^{2}-left(frac{cos 55^{circ}}{sin left(90^{circ}-55^{circ} ight)} ight)^{2}+2 imes frac{1}{2}=(cos55∘sin(90∘−55∘))2−(sin(90∘−55∘)cos55∘)2+2×21 =(cos55∘cos55∘)2−(cos55∘cos55∘)2+1=left(frac{cos 55^{circ}}{cos 55^{circ}} ight)^{2}-left(frac{cos 55^{circ}}{cos 55^{circ}} ight)^{2}+1=(cos55∘cos55∘)2−(cos55∘cos55∘)2+1 =1−1+1=1=1-1+1=1=1−1+1=1 Rate This:NaN / 5 - 1 votesAdd comment
