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1+11+11+11+121+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}} का मूल्य है

a

58\frac{5}{8}

b

813\frac{8}{13}

c

138\frac{13}{8}

d

87\frac{8}{7}

Answer : Option C
Explanation :

अभिव्यक्ति

=1+11+11+11+12=1+11+11+132=1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}}=1+\frac{1}{1+\frac{1}{1+\frac{1}{\frac{3}{2}}}}

=1+11+11+23=1+11+13+23=1+\frac{1}{1+\frac{1}{1+\frac{2}{3}}}=1+\frac{1}{1+\frac{1}{\frac{3+2}{3}}}

=1+11+35=1+15+35=1+58=8+58=138=1+\frac{1}{1+\frac{3}{5}}=1+\frac{1}{\frac{5+3}{5}}=1+\frac{5}{8}=\frac{8+5}{8}=\frac{13}{8}

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