KeerthanaPosted on 1+11+11+11+121+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}}1+1+1+1+21111 का मूल्य है a58\frac{5}{8}85 b813\frac{8}{13}138 c138\frac{13}{8}813 d87\frac{8}{7}78 Answer : Option CExplanation : अभिव्यक्ति =1+11+11+11+12=1+11+11+132=1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}}=1+\frac{1}{1+\frac{1}{1+\frac{1}{\frac{3}{2}}}}=1+1+1+1+21111=1+1+1+23111 =1+11+11+23=1+11+13+23=1+\frac{1}{1+\frac{1}{1+\frac{2}{3}}}=1+\frac{1}{1+\frac{1}{\frac{3+2}{3}}}=1+1+1+3211=1+1+33+211 =1+11+35=1+15+35=1+58=8+58=138=1+\frac{1}{1+\frac{3}{5}}=1+\frac{1}{\frac{5+3}{5}}=1+\frac{5}{8}=\frac{8+5}{8}=\frac{13}{8}=1+1+531=1+55+31=1+85=88+5=813 Rate This:NaN / 5 - 1 votesAdd comment