KeerthanaPosted on अगर 1 N=(6+5)(6−5)frac{1}{mathrm{~N}}=frac{(sqrt{6}+sqrt{5})}{(sqrt{6}-sqrt{5})} N1=(6−5)(6+5), N?mathrm{N} ?N? . का मूल्य क्या है a6−306-sqrt{30}6−30 b6+306+sqrt{30}6+30 c11−23011-2 sqrt{30}11−230 d11+2511+2 sqrt{5}11+25 Answer : Option CExplanation : 1N=6+56−5frac{1}{N}=frac{sqrt{6}+sqrt{5}}{sqrt{6}-sqrt{5}}N1=6−56+5 ∴N=6−56+5=(6−5)(6−5)(6+5)(6−5) herefore quad mathrm{N}=frac{sqrt{6}-sqrt{5}}{sqrt{6}+sqrt{5}}=frac{(sqrt{6}-sqrt{5})(sqrt{6}-sqrt{5})}{(sqrt{6}+sqrt{5})(sqrt{6}-sqrt{5})}∴N=6+56−5=(6+5)(6−5)(6−5)(6−5) (हर को युक्तिसंगत बनाने पर) =(6−5)2(6)2−(5)2=6+5−26×56−5=11−230=frac{(sqrt{6}-sqrt{5})^{2}}{(sqrt{6})^{2}-(sqrt{5})^{2}}=frac{6+5-2 sqrt{6 imes 5}}{6-5}=11-2 sqrt{30}=(6)2−(5)2(6−5)2=6−56+5−26×5=11−230 Rate This:NaN / 5 - 1 votesAdd comment