Keerthana
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अगर 1 N=(6+5)(65)frac{1}{mathrm{~N}}=frac{(sqrt{6}+sqrt{5})}{(sqrt{6}-sqrt{5})}, N?mathrm{N} ? . का मूल्य क्या है

a

6306-sqrt{30}

b

6+306+sqrt{30}

c

1123011-2 sqrt{30}

d

11+2511+2 sqrt{5}

Answer : Option C
Explanation :

1N=6+565frac{1}{N}=frac{sqrt{6}+sqrt{5}}{sqrt{6}-sqrt{5}}

N=656+5=(65)(65)(6+5)(65) herefore quad mathrm{N}=frac{sqrt{6}-sqrt{5}}{sqrt{6}+sqrt{5}}=frac{(sqrt{6}-sqrt{5})(sqrt{6}-sqrt{5})}{(sqrt{6}+sqrt{5})(sqrt{6}-sqrt{5})}

(हर को युक्तिसंगत बनाने पर)

=(65)2(6)2(5)2=6+526×565=11230=frac{(sqrt{6}-sqrt{5})^{2}}{(sqrt{6})^{2}-(sqrt{5})^{2}}=frac{6+5-2 sqrt{6 imes 5}}{6-5}=11-2 sqrt{30}

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