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अगर ab+ba1=0frac{a}{b}+frac{b}{a}-1=0, तो a3+b3a^{3}+b^{3} का मूल्य है

a

3

b

–1

c

1

d

0

Answer : Option D
Explanation :

ab+ba1=0frac{a}{b}+frac{b}{a}-1=0

a2+b2abab=0Rightarrow frac{a^{2}+b^{2}-a b}{a b}=0

a2ab+b2=0Rightarrow a^{2}-a b+b^{2}=0

a3+b3=(a+b)(a2ab+b2)=0a^{3}+b^{3}=(a+b)left(a^{2}-a b+b^{2} ight)=0

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