KeerthanaPosted on अगर secθ+tanθsecθ−tanθ=25179\frac{\sec \theta+\tan \theta}{\sec \theta-\tan \theta}=2 \frac{51}{79}secθ−tanθsecθ+tanθ=27951 तो sinθ\sin \thetasinθ का मूल्य है a3972\frac{39}{72}7239 b65144\frac{65}{144}14465 c3572\frac{35}{72}7235 d91144\frac{91}{144}14491 Answer : Option BExplanation : secθ+tanθsecθ−tanθ=25179=158+5179=20979\frac{\sec \theta+\tan \theta}{\sec \theta-\tan \theta}=2 \frac{51}{79}=\frac{158+51}{79}=\frac{209}{79}secθ−tanθsecθ+tanθ=27951=79158+51=79209 घटक और लाभांश द्वारा, secθ+tanθ+secθ−tanθsecθ+tanθ−secθ+tanθ=209+79209−79\frac{\sec \theta+\tan \theta+\sec \theta-\tan \theta}{\sec \theta+\tan \theta-\sec \theta+\tan \theta}=\frac{209+79}{209-79}secθ+tanθ−secθ+tanθsecθ+tanθ+secθ−tanθ=209−79209+79 ⇒2secθ2tanθ=288130⇒secθtanθ=14465\Rightarrow \frac{2 \sec \theta}{2 \tan \theta}=\frac{288}{130} \Rightarrow \frac{\sec \theta}{\tan \theta}=\frac{144}{65}⇒2tanθ2secθ=130288⇒tanθsecθ=65144 ∴sinθ=tanθsecθ=65144\therefore \quad \sin \theta=\frac{\tan \theta}{\sec \theta}=\frac{65}{144}∴sinθ=secθtanθ=14465 Rate This:NaN / 5 - 1 votesAdd comment