KeerthanaPosted on अगर x = z = 225 और y = 226 तो का मूल्य : x3 + y 3 + z3< /sup> – 3xyz is a765 b676 c576 d674 Answer : Option BExplanation : x = z = 225, y = 226 ∴ x + y + z = 225 + 226 + 225 = 676 ∴ x³ + y³ + z³ – 3 xyz =12(x+y+z)[(x−y)2+(y−z)2+(z−x)2]=\frac{1}{2}(x+y+z)\left[(x-y)^{2}+(y-z)^{2}+(z-x)^{2}\right]=21(x+y+z)[(x−y)2+(y−z)2+(z−x)2] =12×676[(225−226)2+(226−225)2+(225−=\frac{1}{2} \times 676\left[(225-226)^{2}+(226-225)^{2}+(225-\right.=21×676[(225−226)2+(226−225)2+(225− 225)2]=12×676×(1+1)=676\left.225)^{2}\right]=\frac{1}{2} \times 676 \times(1+1)=676225)2]=21×676×(1+1)=676 Rate This:NaN / 5 - 1 votesAdd comment