KeerthanaPosted on If sinx=13sin x=frac{1}{3}sinx=31, then the value of sin3xsin 3 xsin3x will be a2713frac{27}{13}1327 b2723frac{27}{23}2327 c1327frac{13}{27}2713 d2327frac{23}{27}2723 Answer : Option DExplanation : Here, sinx=13sin x=frac{1}{3}sinx=31 We know that, sin3x = 3sinx – 4sin3x On putting the value of sinx, we get sin3x=3⋅(13)−4⋅(13)3sin 3 x=3 cdotleft(frac{1}{3} ight)-4 cdotleft(frac{1}{3} ight)^{3}sin3x=3⋅(31)−4⋅(31)3 =1−427=27−427=1-frac{4}{27}=frac{27-4}{27}=1−274=2727−4 sin3x=2327sin 3 x=frac{23}{27}sin3x=2723 Rate This:NaN / 5 - 1 votesAdd comment