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त्रिभुज में ABC,BAC=75,ABC=45BCmathrm{ABC}, angle mathrm{BAC}=75^{circ}, angle mathrm{ABC}=45^{circ} cdot overline{mathrm{BC}} Dmathrm{D} में उत्पादित किया जाता है। अगर ACD=xangle mathrm{ACD}=x^{circ}, तो x3%frac{x}{3} \% of 6060^{circ} है

a

15°

b

48°

c

24°

d

30°

Answer : Option C
Explanation :

ACB=1807545angle mathrm{ACB}=180^{circ}-75^{circ}-45^{circ}

=60=60^{circ}

ACD=18060=120=xangle mathrm{ACD}=180^{circ}-60^{circ}=120^{circ}=x

x3% herefore frac{x}{3} \% of 60=60×120300=2460^{circ}=60 imes frac{120}{300}=24^{circ}

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