KeerthanaPosted on यदि 4a−4a+3=04 a-\frac{4}{a}+3=04a−a4+3=0 तो : a3−1a3+3=?a^{3}-\frac{1}{a^{3}}+3=?a3−a31+3=? का मूल्य a316\frac{3}{16}163 b716\frac{7}{16}167 c2164\frac{21}{64}6421 d2116\frac{21}{16}1621 Answer : Option CExplanation : 4a−4a=−34 a-\frac{4}{a}=-34a−a4=−3 4 से भाग देने पर, ⇒a−1a=−34\Rightarrow a-\frac{1}{a}=\frac{-3}{4}⇒a−a1=4−3 ∴a3−1a3=(a−1a)3+3a×1a(a−1a)\therefore \quad a^{3}-\frac{1}{a^{3}}=\left(a-\frac{1}{a}\right)^{3}+3 a \times \frac{1}{a}\left(a-\frac{1}{a}\right)∴a3−a31=(a−a1)3+3a×a1(a−a1) =(−34)3+3×−34=\left(\frac{-3}{4}\right)^{3}+3 \times \frac{-3}{4}=(4−3)3+3×4−3 =−2764−94=−27−14464=−17164=-\frac{27}{64}-\frac{9}{4}=\frac{-27-144}{64}=\frac{-171}{64}=−6427−49=64−27−144=64−171 ∴a3−1a3+3=−17164+3=−171+19264=2164\therefore \quad a^{3}-\frac{1}{a^{3}}+3=\frac{-171}{64}+3=\frac{-171+192}{64}=\frac{21}{64}∴a3−a31+3=64−171+3=64−171+192=6421 Rate This:NaN / 5 - 1 votesAdd comment
