KeerthanaPosted on यदि a+b +1 = 0, तो (a3+b3 +1 – 3ab) का मूल्य है ; a0 b3 c1 d– 1 Answer : Option AExplanation : If a+b+c=0;a3+b3+c3−3abca+b+c=0 ; a^{3}+b^{3}+c^{3}-3 a b ca+b+c=0;a3+b3+c3−3abc =(a+b+c)×(a2+b2+c2+ab+bc+ca)=(a+b+c) imesleft(a^{2}+b^{2}+c^{2}+a b+b c+c a ight)=(a+b+c)×(a2+b2+c2+ab+bc+ca) then a3+b3+c3−3abc=0a^{3}+b^{3}+c^{3}-3 a b c=0a3+b3+c3−3abc=0 Rate This:NaN / 5 - 1 votesAdd comment