Keerthana
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यदि x27x+1=0x^{2}-7 x+1=0, तो (x+1x)?\left(x+\frac{1}{x}\right) ? का मूल्य क्या है?

a

7

b

3

c

51

d

47

Answer : Option A
Explanation :

x27x+1=0x^{2}-7 x+1=0

x2+1=210x\Rightarrow x^{2}+1=2 \sqrt{10} x

x2+1x=210\Rightarrow \frac{x^{2}+1}{x}=2 \sqrt{10}

x+1x=210\Rightarrow x+\frac{1}{x}=2 \sqrt{10}

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