Keerthana
Posted on

41+tan2α+11+cot2α+3sin2αfrac{4}{1+ an ^{2} alpha}+frac{1}{1+cot ^{2} alpha}+3 sin ^{2} alpha का मूल्य

a

4

b

–1

c

3

d

2

Answer : Option A
Explanation :
41+tan2α+11+cot2α+3sin2αfrac{4}{1+ an ^{2} alpha}+frac{1}{1+cot ^{2} alpha}+3 sin ^{2} alpha =4sec2α+1cosec2α+3sin2α=frac{4}{sec ^{2} alpha}+frac{1}{operatorname{cosec}^{2} alpha}+3 sin ^{2} alpha =4cos2α+sin2α+3sin2α=4 cos ^{2} alpha+sin ^{2} alpha+3 sin ^{2} alpha =4(cos2α+sin2α)=4=4left(cos ^{2} alpha+sin ^{2} alpha ight)=4

विकल्प:

मान लीजिए α = 45°

41+tan2α+11+cot2α+3sin2αfrac{4}{1+ an ^{2} alpha}+frac{1}{1+cot ^{2} alpha}+3 sin ^{2} alpha

tan 45° = cot 45° = 1

=42+12+3×(12)2=82=4=frac{4}{2}+frac{1}{2}+3 imesleft(frac{1}{sqrt{2}} ight)^{2}=frac{8}{2}=4

Rate This:
NaN / 5 - 1 votes
Profile photo for Dasaradhan Gajendra