KeerthanaPosted on 41+tan2α+11+cot2α+3sin2αfrac{4}{1+ an ^{2} alpha}+frac{1}{1+cot ^{2} alpha}+3 sin ^{2} alpha1+tan2α4+1+cot2α1+3sin2α का मूल्य a4 b–1 c3 d2 Answer : Option AExplanation : 41+tan2α+11+cot2α+3sin2αfrac{4}{1+ an ^{2} alpha}+frac{1}{1+cot ^{2} alpha}+3 sin ^{2} alpha1+tan2α4+1+cot2α1+3sin2α =4sec2α+1cosec2α+3sin2α=frac{4}{sec ^{2} alpha}+frac{1}{operatorname{cosec}^{2} alpha}+3 sin ^{2} alpha=sec2α4+cosec2α1+3sin2α =4cos2α+sin2α+3sin2α=4 cos ^{2} alpha+sin ^{2} alpha+3 sin ^{2} alpha=4cos2α+sin2α+3sin2α =4(cos2α+sin2α)=4=4left(cos ^{2} alpha+sin ^{2} alpha ight)=4=4(cos2α+sin2α)=4 विकल्प: मान लीजिए α = 45° 41+tan2α+11+cot2α+3sin2αfrac{4}{1+ an ^{2} alpha}+frac{1}{1+cot ^{2} alpha}+3 sin ^{2} alpha1+tan2α4+1+cot2α1+3sin2α tan 45° = cot 45° = 1 =42+12+3×(12)2=82=4=frac{4}{2}+frac{1}{2}+3 imesleft(frac{1}{sqrt{2}} ight)^{2}=frac{8}{2}=4=24+21+3×(21)2=28=4 Rate This:NaN / 5 - 1 votesAdd comment