KeerthanaPosted on A का मूल्य क्या है? A=(cosθsin(90∘+θ)+sin(−θ)sin(180∘+θ)−tan(90∘+θ)cotθ)?A=left(frac{cos heta}{sin left(90^{circ}+ heta ight)}+frac{sin (- heta)}{sin left(180^{circ}+ heta ight)}-frac{ an left(90^{circ}+ heta ight)}{cot heta} ight) ?A=(sin(90∘+θ)cosθ+sin(180∘+θ)sin(−θ)−cotθtan(90∘+θ))? a4 b2 c1 d3 Answer : Option DExplanation : cosθsin(90∘+θ)+sin(−θ)sin(180∘+θ)−tan(90∘+θ)cotθfrac{cos heta}{sin left(90^{circ}+ heta ight)}+frac{sin (- heta)}{sin left(180^{circ}+ heta ight)}-frac{ an left(90^{circ}+ heta ight)}{cot heta}sin(90∘+θ)cosθ+sin(180∘+θ)sin(−θ)−cotθtan(90∘+θ) =cosθcosθ+(−sinθ−sinθ)+cotθcotθ=1+1+1=frac{cos heta}{cos heta}+left(frac{-sin heta}{-sin heta} ight)+frac{cot heta}{cot heta}=1+1+1=cosθcosθ+(−sinθ−sinθ)+cotθcotθ=1+1+1 =3=3=3 Rate This:NaN / 5 - 1 votesAdd comment
