KeerthanaPosted on A basket contains 6 red, 5 green and 8 blue balls. If four balls are picked at random, what is the probability that all four of them are either red or any two out of the four are green? a 51292frac{5}{{1292}}12925 b 9253876frac{{925}}{{3876}}3876925 c 3591938frac{{359}}{{1938}}1938359 d 113876frac{{11}}{{3876}}387611 e None of these Answer : Option BExplanation : n(E)=6C4+5C2×14C2nleft( E ight) = 6{C_4} + 5{C_2} imes 14{C_2}n(E)=6C4+5C2×14C2 P(E)=6C4+5C2×14C219C4=15+9102876=9253876Pleft( E ight) = frac{{6{C_4} + 5{C_2} imes 14{C_2}}}{{19{C_4}}} = frac{{15 + 910}}{{2876}} = frac{{925}}{{3876}}P(E)=19C46C4+5C2×14C2=287615+910=3876925 Rate This:NaN / 5 - 1 votesAdd comment