Keerthana
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A basket contains 6 red, 5 green and 8 blue balls. If four balls are picked at random, what is the probability that all four of them are either red or any two out of the four are green?

a

51292frac{5}{{1292}}

b

9253876frac{{925}}{{3876}}

c

3591938frac{{359}}{{1938}}

d

113876frac{{11}}{{3876}}

e

None of these

Answer : Option B
Explanation :

n(E)=6C4+5C2×14C2nleft( E ight) = 6{C_4} + 5{C_2} imes 14{C_2}

P(E)=6C4+5C2×14C219C4=15+9102876=9253876Pleft( E ight) = frac{{6{C_4} + 5{C_2} imes 14{C_2}}}{{19{C_4}}} = frac{{15 + 910}}{{2876}} = frac{{925}}{{3876}}

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