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A bullet of mass ’m’ and velocity ’a’ is fired in to a large block of wood of mass ’M’. The final velocity of the system is

a

m+Mmafrac{m+M}{m} a

b

mm+Mafrac{m}{m+M} a

c

m+MMafrac{m+M}{M} a

d

Mm+Mafrac{M}{m+M} a

Answer : Option B
Explanation :

If v is the final velocity, then according to the principle of conservation of momentum

m1v1+m2v2=(m1+m2)vmathrm{m}_{1} mathrm{v}_{1}+mathrm{m}_{2} mathrm{v}_{2}=left(mathrm{m}_{1}+mathrm{m}_{2} ight) mathrm{v} or, v=m1v1+m2v2/(m1+m2)mathrm{v}=mathrm{m}_{1} mathrm{v}_{1}+mathrm{m}_{2} mathrm{v}_{2} /left(mathrm{m}_{1}+mathrm{m}_{2} ight)

Using values from the question, v = m a + 0/ (m + M) = ma/ (m + M)

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