A can do a piece of work in 12 days. B is 50% more efficient than A. In how many days B will finish the same work ?

Time taken by $mathrm{B}=12 imes frac{100}{150}=8$ days Alternative: Fraction of $50 \%=+frac{1}{2} uparrow^{3}$

Total work = Time × Efficiency

Time taken by B complete the work

$=frac{ ext { Total work }}{ ext { Efficiency of B }}$

$=frac{12 imes 2}{3}=8$ days