A three digits number X, which tenth’s place digit is 3. If the unit digit and hundred place digit of number x interchanged thus the number formed is 396 more than the previous one. If the sum of unit digit and hundred digit is 14, then what is the number?

Let numbere x be = abc

So, According to question

b = 3

(100c – 10b – a) – (100a – 10b – c)

=396 99????−99????=396

????−????=4 ……………………………………………(i)

And it is given that

c + a = 14 ………………………………………(ii)

Solving (i) & (ii)

c = 9

a = 5

so, number is = 539