Keerthana
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If αalpha and βeta are the roots of the equation x2x+3x^{2}-x+3 =0=0, then what is the value of (α4+β4)?left(alpha^{4}+eta^{4} ight) ?

a

9

b

11

c

7

d

13

Answer : Option C
Explanation :

If the roots of quadratic equation ax2 + bx + c

= 0 be D and Ethen

α+β=ba;αβ=caalpha+eta=-frac{b}{a} ; alpha eta=frac{c}{a}

herefore For equation x2x+3=0x^{2}-x+3=0,

α+β=1;αβ=3alpha+eta=1 ; alpha eta=3

α4+β4=(α2)2+(β2)2=(α2+β2)22α2β2 herefore alpha^{4}+eta^{4}=left(alpha^{2} ight)^{2}+left(eta^{2} ight)^{2}=left(alpha^{2}+eta^{2} ight)^{2}-2 alpha^{2} eta^{2}

={(a+β)22αβ}22α2β2=left{(a+eta)^{2}-2 alpha eta ight}^{2}-2 alpha^{2} eta^{2}

=(12×3)22×9=(5)218=2518=7=(1-2 imes 3)^{2}-2 imes 9=(-5)^{2}-18=25-18=7

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