AB is a diameter of a circle with centre at O. DC is a chord of it such that DC || AB. If ∠BAC = 20°, then ∠ ADC is equal to

Answer : Option A

Explanation :

∴ ∠BAC = ∠BDC = 20°

∠ADB = 90° (Angle of semi-circle)

∴ ∠ ADC = 90° + 20° = 110°