Directions(Q.11 to Q.15 ):

In the following two equations questions numbered (I) and (II) are given. You have to solve both equations and Give answer

I. ${x^2} - 7x + 12 = 0$

II. ${y^2} - 8y + 12 = 0$

I. ${x^2} - 7x + 12 = 0$

${x^2} - 4x - 3x + 12 = 0$

$left( {x - 4} ight)left( {x - 3} ight) = 0$

$x = 3,4$II. ${y^2} - 8y + 12 = 0$

${y^2} - 6y - 2y + 12 = 0$

$left( {y - 6} ight)left( {y - 2} ight) = 0$

$y = 2,6$

No relation can be established