Directions(Q.16 to Q.25 ):

A mixture contains wine and water in the ratio 3 : 2 and another mixture contains them in the ratio 4 : 5. How many litres of the latter must be mixed with 3 litres of the former so that the resultant mixture may contain equal quantities of wine and water ?

$1frac{2}{3}{ m{litre}}$

$5frac{2}{5}$ ${ m{litre}}$

$4frac{1}{2}{ m{litre}}$

$3frac{3}{4}$ litre

none of these

Answer : Option B

Explanation :

Ratio $= frac{1}{{18}}:frac{1}{{10}}$

= 10 : 18 = 5 : 9

Required Quantity $= frac{3}{5} imes 9$

$= frac{{27}}{5} = 5frac{2}{5}$ litre

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