Directions(Q.24 to Q.28 ):
In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.
In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.

I. $20{x^2} - x - 12 = 0$
II. $20{y^2} + 27y + 9 = 0$

If x > y

If x ≥y

If x < y

If x ≤y

If x = y or the relationship cannot be established

Answer : Option

Explanation :

20x² – x – 12 = 0

⇒x = $frac{{ + 16}}{{20}},frac{{ - 15}}{{20}}$

$x = + frac{3}{5}, - frac{3}{4}$

20y²+ 27y + 9 = 0

$y = frac{{ - 15}}{{20}},frac{{ - 12}}{{20}}$

$= - frac{3}{4},frac{{ - 3}}{5}$

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