KeerthanaPosted on Directions(Q.25 to Q.35 ): (i) 12x² + 11x + 2 = 0 (ii) 12y²+ 7y + 1 = 0 a x ≥ y b x = y or no relation can be established between x & y. c x < y d x ≤ y e x > y Answer : Option BExplanation : 12x2+8x+3x+2=012{x^2} + 8x + 3x + 2 = 012x2+8x+3x+2=0 4x(3x+2)+1(3x+2)=04xleft( {3x + 2} ight) + 1left( {3x + 2} ight) = 04x(3x+2)+1(3x+2)=0 x=−23,−14x = frac{{ - 2}}{3},frac{{ - 1}}{4}x=3−2,4−1 12y2+7y+1=012{y^2} + 7y + 1 = 012y2+7y+1=0 12y2+4y+3y+1=012{y^2} + 4y + 3y + 1 = 012y2+4y+3y+1=0 4y(3y+1)+1(3y+1)=04yleft( {3y + 1} ight) + 1left( {3y + 1} ight) = 04y(3y+1)+1(3y+1)=0 y=−13,−14y = frac{{ - 1}}{3},frac{{ - 1}}{4}y=3−1,4−1 No relation between x and y Rate This:NaN / 5 - 1 votesAdd comment