Directions(Q.35 to Q.40 ):

A bar graph is given below which shows hat sold by seller A and seller B on five days.

Total number of hats sold by A and B together on Wednesday is how much percentage more than the number of hats sold by A and B together on Tuesday:

$15frac{2}{3}{ m{\% }}$

$8frac{1}{3}{ m{\% }}$

$16frac{2}{5}{ m{\% }}$

$16frac{2}{3}{ m{\% }}$

$21frac{3}{7}{ m{\% }}$

Answer : Option D

Explanation :

Total no. of hats sold on Wednesday

= 64 + 48 = 112

Total no. of hats sold on Tuesday

= 60 + 36 = 96

Desired Percentage = $frac{{112 - 96}}{{96}} imes 100$

$= 16frac{2}{3}{ m{\% }}$

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