KeerthanaPosted on Equation of a line is taken as 3x – 4y + 5 = 0. Its slope and intercept on y-axis ; a(34,−54)left(frac{3}{4}, frac{-5}{4} ight)(43,4−5) b(34,54)left(frac{3}{4}, frac{5}{4} ight)(43,45) c(−34,−54)left(frac{-3}{4}, frac{-5}{4} ight)(4−3,4−5) d(54,34)left(frac{5}{4}, frac{3}{4} ight)(45,43) Answer : Option BExplanation : Here, 3x – 4y + 5 = 0 ⇒ –4y = – 3x – 5 y=−3−4x−5−4y=frac{-3}{-4} x frac{-5}{-4}y=−4−3x−4−5 y=34x+54y=frac{3}{4} x+frac{5}{4}y=43x+45 Compare it with, y = mx + c we get m=34m=frac{3}{4} quadm=43 and c=54quad c=frac{5}{4}c=45 Rate This:NaN / 5 - 1 votesAdd comment