I. $sqrt {361} x + sqrt {16} = 0$

II. $sqrt {441y} + 4 = 0$

(i) $sqrt {361} x + sqrt {16} = 0$

19 x + 4 = 0

x = $- frac{4}{{19}}$

(ii) $sqrt {441y} + 4 = 0$

$21sqrt y + 4 = 0$

$sqrt y = - frac{4}{{21}}$

$y = - frac{{16}}{{441}}$

Hence x < y