KeerthanaPosted on I. 3x2−7x+4=03{x^2} - 7x + 4 = 03x2−7x+4=0II.2y2−9y+10=02{y^2} - 9y + 10 = 02y2−9y+10=0 a if x>y b if x≥y c if xd if x ≤y e if x = y or no relation can be established between x and y. Answer : Option CExplanation : I. 3x2−7x+4=03{x^2} - 7x + 4 = 03x2−7x+4=0 ⇒3x2−4x−3x+4=0 Rightarrow 3{x^2} - 4x - 3x + 4 = 0⇒3x2−4x−3x+4=0 ⇒(3x−4)(x−1)=0 Rightarrow left( {3x - 4} ight)left( {x - 1} ight) = 0⇒(3x−4)(x−1)=0 x=43or1x = frac{4}{3}{ m{or}}1x=34or1II. 2y2−9y+10=02{y^2} - 9y + 10 = 02y2−9y+10=0 ⇒2y2−4y−5y+10=0 Rightarrow 2{y^2} - 4y - 5y + 10 = 0⇒2y2−4y−5y+10=0 ⇒(2y−5)(y−2)=0 Rightarrow left( {2y - 5} ight)left( {y - 2} ight) = 0⇒(2y−5)(y−2)=0 ⇒y=52or2 Rightarrow y = frac{5}{2}{ m{or}}2⇒y=25or2 y>xy > xy>x Rate This:NaN / 5 - 1 votesAdd comment