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I. 3x27x+4=03{x^2} - 7x + 4 = 0II.2y29y+10=02{y^2} - 9y + 10 = 0

a

if x>y

b

if x≥y

c

if x

d

if x ≤y

e

if x = y or no relation can be established between x and y.

Answer : Option C
Explanation :

I. 3x27x+4=03{x^2} - 7x + 4 = 0

3x24x3x+4=0 Rightarrow 3{x^2} - 4x - 3x + 4 = 0

(3x4)(x1)=0 Rightarrow left( {3x - 4} ight)left( {x - 1} ight) = 0

x=43or1x = frac{4}{3}{ m{or}}1II. 2y29y+10=02{y^2} - 9y + 10 = 0

2y24y5y+10=0 Rightarrow 2{y^2} - 4y - 5y + 10 = 0

(2y5)(y2)=0 Rightarrow left( {2y - 5} ight)left( {y - 2} ight) = 0

y=52or2 Rightarrow y = frac{5}{2}{ m{or}}2

y>xy > x

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