KeerthanaPosted on I. 5x2+17x+6=05{x^2} + 17x + 6 = 05x2+17x+6=0 II. 2y2+11y+12=02{y^2} + 11y + 12 = 02y2+11y+12=0 a if x>y b if x≥y c if xd if x ≤y e if x = y or no relation can be established between x and y. Answer : Option EExplanation : I. 5x2+17x+6=0;{f{I}}.;;5{x^2} + 17x + 6 = 0I.5x2+17x+6=0 5x2+15x+2x+6=05{x^2} + 15x + 2x + 6 = 05x2+15x+2x+6=0 5x(x+3)+2(x+3)=05xleft( {x + 3} ight) + 2left( {x + 3} ight) = 05x(x+3)+2(x+3)=0 x=−3,−25x = - 3, - frac{2}{5}x=−3,−52 II. 2y2+11y+12=0{f{II}}.;;2{y^2} + 11y + 12 = 0II.2y2+11y+12=0 2y2+8y+3y+12=02{y^2} + 8y + 3y + 12 = 02y2+8y+3y+12=0 2y(y+4)+3(y+4)=02yleft( {y + 4} ight) + 3left( {y + 4} ight) = 02y(y+4)+3(y+4)=0 y=−4,−32y = - 4, - frac{3}{2}y=−4,−23 Hence, No relation Rate This:NaN / 5 - 1 votesAdd comment