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I. 5x2+17x+6=05{x^2} + 17x + 6 = 0

II. 2y2+11y+12=02{y^2} + 11y + 12 = 0

a

if x>y

b

if x≥y

c

if x

d

if x ≤y

e

if x = y or no relation can be established between x and y.

Answer : Option E
Explanation :

  I.    5x2+17x+6=0;{f{I}}.;;5{x^2} + 17x + 6 = 0

5x2+15x+2x+6=05{x^2} + 15x + 2x + 6 = 0

5x(x+3)+2(x+3)=05xleft( {x + 3} ight) + 2left( {x + 3} ight) = 0

x=3,25x = - 3, - frac{2}{5}

II.    2y2+11y+12=0{f{II}}.;;2{y^2} + 11y + 12 = 0

2y2+8y+3y+12=02{y^2} + 8y + 3y + 12 = 0

2y(y+4)+3(y+4)=02yleft( {y + 4} ight) + 3left( {y + 4} ight) = 0

y=4,32y = - 4, - frac{3}{2}

Hence, No relation

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