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I. 7x219x+10=07{x^2} - 19x + 10 = 0

II. 8y2+2y3=08{y^2} + 2y - 3 = 0

a

if x>y

b

if x≥y

c

if x

d

if x ≤y

e

if x = y or no relation can be established between x and y.

Answer : Option A
Explanation :

I. 7x219x+10=07{x^2} - 19x + 10 = 0

7x214x5x+10=07{x^2} - 14x - 5x + 10 = 0

7x(x2)5(x2)=07xleft( {x - 2} ight) - 5left( {x - 2} ight) = 0

x=2,57x = 2,frac{5}{7}

II. 8y2+2y3=08{y^2} + 2y - 3 = 0

8y2+6y4y3=08{y^2} + 6y - 4y - 3 = 0

2y(4y+3)1(4y+3)=02yleft( {4y + 3} ight) - 1left( {4y + 3} ight) = 0

y=34,12y = frac{{ - 3}}{4},frac{1}{2}

x>yx > y

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