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If (a+b+c)=0(a+b+c)=0, then (a2bc+b2ca+c2ab)left(frac{a^{2}}{b c}+frac{b^{2}}{c a}+frac{c^{2}}{a b} ight) is

a

3

b

–1

c

1

d

0

Answer : Option A
Explanation :

अगर ए + बी + सी= 0

a3 + b3 + c3 – 3abc = 0

अभिव्यक्ति=a2bc+b2ca+c2ab=frac{a^{2}}{b c}+frac{b^{2}}{c a}+frac{c^{2}}{a b}

=a3+b3+c3abc=3abcabc=3=frac{a^{3}+b^{3}+c^{3}}{a b c}=frac{3 a b c}{a b c}=3

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