KeerthanaPosted on If (a+b+c)=0(a+b+c)=0(a+b+c)=0, then (a2bc+b2ca+c2ab)left(frac{a^{2}}{b c}+frac{b^{2}}{c a}+frac{c^{2}}{a b} ight)(bca2+cab2+abc2) is a3 b–1 c1 d0 Answer : Option AExplanation : अगर ए + बी + सी= 0 a3 + b3 + c3 – 3abc = 0 अभिव्यक्ति=a2bc+b2ca+c2ab=frac{a^{2}}{b c}+frac{b^{2}}{c a}+frac{c^{2}}{a b}=bca2+cab2+abc2 =a3+b3+c3abc=3abcabc=3=frac{a^{3}+b^{3}+c^{3}}{a b c}=frac{3 a b c}{a b c}=3=abca3+b3+c3=abc3abc=3 Rate This:NaN / 5 - 1 votesAdd comment