If secθ + tanθ = 2 then the value of sec T is ;fn secT + tanT = 2

$\sec \theta+\tan \theta=2 \quad \ldots \ldots$ (i)

$\therefore \sec ^{2} \theta-\tan ^{2} \theta=1$

$\Rightarrow(\sec \theta+\tan \theta)(\sec \theta-\tan \theta)=1$

$\Rightarrow \sec \theta-\tan \theta=\frac{1}{2}$

By adding equations (i) and (ii),

$\therefore \quad \sec \theta+\tan \theta+\sec \theta-\tan \theta=2+\frac{1}{2}=\frac{5}{2}$

$\Rightarrow 2 \sec \theta=\frac{5}{2} \Rightarrow \sec \theta=\frac{5}{4}$