KeerthanaPosted on If 2a−(2a)+4=02 a-left(frac{2}{a} ight)+4=02a−(a2)+4=0, then what is the value of a3−a^{3}-a3− (1a3)+14?left(frac{1}{a^{3}} ight)+14 ?(a31)+14? a–12 b–14 c14 d0 Answer : Option DExplanation : 2a−2a+4=02 a-frac{2}{a}+4=02a−a2+4=0 ⇒2(a−1a+2)=0Rightarrow 2left(a-frac{1}{a}+2 ight)=0⇒2(a−a1+2)=0 ⇒a−1a=−2Rightarrow a-frac{1}{a}=-2⇒a−a1=−2 On cubing both sides, (a−1a)3=−8left(a-frac{1}{a} ight)^{3}=-8(a−a1)3=−8 ⇒a3−1a3−3(a−1a)=−8Rightarrow a^{3}-frac{1}{a^{3}}-3left(a-frac{1}{a} ight)=-8⇒a3−a31−3(a−a1)=−8 ⇒a3−1a3−3×−2=−8Rightarrow a^{3}-frac{1}{a^{3}}-3 imes-2=-8⇒a3−a31−3×−2=−8 ⇒a3−1a3+6+8=0Rightarrow a^{3}-frac{1}{a^{3}}+6+8=0⇒a3−a31+6+8=0 ⇒a3−1a3+14=0Rightarrow a^{3}-frac{1}{a^{3}}+14=0⇒a3−a31+14=0 Rate This:NaN / 5 - 1 votesAdd comment