KeerthanaPosted on If a + b + c + d = 1, then the maximum value of (1 + a) (1 + b) (1 + c) (1 + d) is a1 b(12)3\left(\frac{1}{2}\right)^{3}(21)3 c(34)3\left(\frac{3}{4}\right)^{3}(43)3 d(54)4\left(\frac{5}{4}\right)^{4}(45)4 Answer : Option DExplanation : For maximum value, a=b=c=d=14a=b=c=d=\frac{1}{4}a=b=c=d=41 ∴(1+a)(1+b)(1+c)(1+d)=(54)4\therefore(1+a)(1+b)(1+c)(1+d)=\left(\frac{5}{4}\right)^{4}∴(1+a)(1+b)(1+c)(1+d)=(45)4 Rate This:NaN / 5 - 1 votesAdd comment