If $frac{a}{b}+frac{b}{a}-1=0$, then the value of $a^{3}+b^{3}$ is

$frac{a}{b}+frac{b}{a}-1=0$

$Rightarrow frac{a^{2}+b^{2}-a b}{a b}=0$

$Rightarrow a^{2}-a b+b^{2}=0$

$a^{3}+b^{3}=(a+b)left(a^{2}-a b+b^{2} ight)=0$