KeerthanaPosted on If sinx .cosy + cosx.siny = 1, then the value of x + y will be aπ4frac{pi}{4}4π bπ2frac{pi}{2}2π c−π2-frac{pi}{2}−2π dπ3frac{pi}{3}3π Answer : Option BExplanation : Here, sinx⋅cosy+cosx⋅siny=1sin x cdot cos y+cos x cdot sin y=1sinx⋅cosy+cosx⋅siny=1 ⇒sin(x+y)=1Rightarrow sin (x+y)=1⇒sin(x+y)=1 [ sin (A + B) = sinA cosB + cosA sinB] ⇒sin(x+y)=sinπ2Rightarrow sin (x+y)=sin frac{pi}{2}⇒sin(x+y)=sin2π ⇒x+y=π2Rightarrow x+y=frac{pi}{2}⇒x+y=2π Rate This:NaN / 5 - 1 votesAdd comment