KeerthanaPosted on If tan 7θ tan 2θ = 1, then the value of tan 3θ is a3\sqrt{3}3 b−13-\frac{1}{\sqrt{3}}−31 c13\frac{1}{\sqrt{3}}31 d−3-\sqrt{3}−3 Answer : Option CExplanation : tan 7θ . tan 2θ = 1 ⇒tan7θ=1tan2θ=cot2θ\Rightarrow \tan 7 \theta=\frac{1}{\tan 2 \theta}=\cot 2 \theta⇒tan7θ=tan2θ1=cot2θ ⇒tan7θ=tan(90∘−2θ)\Rightarrow \tan 7 \theta=\tan \left(90^{\circ}-2 \theta\right)⇒tan7θ=tan(90∘−2θ) ⇒7θ=90∘−2θ\Rightarrow 7 \theta=90^{\circ}-2 \theta⇒7θ=90∘−2θ ⇒9θ=90∘⇒θ=10∘\Rightarrow 9 \theta=90^{\circ} \Rightarrow \theta=10^{\circ}⇒9θ=90∘⇒θ=10∘ ∴tan3θ=tan30∘=13\therefore \tan 3 \theta=\tan 30^{\circ}=\frac{1}{\sqrt{3}}∴tan3θ=tan30∘=31 Rate This:NaN / 5 - 1 votesAdd comment