KeerthanaPosted on If the height of a cone is 15 cm and its volume is 770 cm3, find the radius of its base? (π=227)\left(\pi=\frac{22}{7}\right)(π=722) a$7 \sqrt{10} \mathrm{~cm} b$7 \mathrm{~cm} c$0.7 \mathrm{~cm} d$0.07 \mathrm{~cm} Answer : Option BExplanation : Volume of cone =13πr2h=\frac{1}{3} \pi r^{2} h=31πr2h ⇒13×227×r2×15=770\Rightarrow \frac{1}{3} \times \frac{22}{7} \times r^{2} \times 15=770⇒31×722×r2×15=770 ⇒r2=770×3×722×15=49\Rightarrow r^{2}=\frac{770 \times 3 \times 7}{22 \times 15}=49⇒r2=22×15770×3×7=49 ⇒r=49=7 cm.\Rightarrow r=\sqrt{49}=7 \mathrm{~cm} .⇒r=49=7 cm. Rate This:NaN / 5 - 1 votesAdd comment