If the vertices of a quadrilateral are A(– 2, 6), B(1, 2), C(10, 4) and D(7, 8). Then the equation of diagonal AC will be ?

Answer : Option A

Explanation :

We know that, equation of line is $frac{y-y_{1}}{y_{2}-y_{1}}=frac{x-x_{1}}{x_{2}-x_{1}}$ Equation of diagonal AC, will be $frac{y-6}{4-6}=frac{x+2}{10+2}$

12y – 72 = –2x – 4

2x + 12y = –4 + 72

2x + 12y = 68

⇒ x + 6y = 34