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If x = a – b, y = b – c, z = c – a, then the numerical value of the algebraic expression x3 + y3 + z3 – 3xyz will be

a

a + b + c

b

0

c

4 (a + b + c)

d

3 abc

Answer : Option B
Explanation :

x + y + z = a – b + b – c + c – a = 0

∴ x³ + y³ + z³ –3xyz = 0

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