Keerthana
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If x = r cos θ cos φ, y = r cos θ sin φ and z = r sin θ, then the value of x² + y² + z² is

a

r2r^{2}

b

1r2frac{1}{r^{2}}

c

rr

d

1rfrac{1}{r}

Answer : Option A
Explanation :

x = r cosθ . cosφ

y = r cos sinφ

z = r sinθ

z = r sin

∴ x2 + y2 + z2 = r2 cos2θ. cos2φ + r2cos2θ . sin2φ+

r2 sin2θ

= r2cos2θ(cos2φ + sin2φ) + r2 sin2θ

= r2cos2θ+r2φsin2θ

= r2 (cos2θ+ sin2θ) = r2

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